# Linear difference equation

## Papers overview

Semantic Scholar uses AI to extract papers important to this topic.

2013

2013

- 2013

Introduction In the past few years, oscillation and non-oscillation theory of second-order linear and nonlinear difference… (More)

Is this relevant?

2008

2008

- 2008

Solutions of a homogeneous (r+ l)-term linear difference equation are given in two different forms. One involves the elements of… (More)

Is this relevant?

2007

2007

- Computers & Mathematics with Applications
- 2007

We establish new conjugacy criteria for the second order linear difference equation 1(rk1xk)+ qk xk+1 = 0, k ∈ Z. To this goal… (More)

Is this relevant?

2006

2006

- 2006

In the paper sufficient conditions for the difference equation r qx = i CLn X n+i i=o to have a solution which tends to a… (More)

Is this relevant?

2006

2006

- Applied Mathematics and Computation
- 2006

Our aim in this paper is to investigate the dynamics of difference equation 0096-3 doi:10 * Co E-m ynþ1 1⁄4 yn þ pyn k yn þ q ; n… (More)

Is this relevant?

2005

2005

- 2005

In this paper we study boundary value problems for perturbed second-order linear differenc tions with a small parameter. The… (More)

Is this relevant?

2005

2005

- Math. Comput.
- 2005

Two linearly independent asymptotic solutions are constructed for the second-order linear difference equation yn+1(x) − (Anx + Bn… (More)

Is this relevant?

2003

2003

- 2003

The second order linear difference equation (1) ∆(rk∆xk) + ckxk+1 = 0, where rk 6= 0 and k ∈ , is considered as a special type of… (More)

Is this relevant?

Highly Cited

1995

Highly Cited

1995

- ISSAC
- 1995

We propose a simple algorithm to construct a polynomial divisible by the denominator of any rational solution of a linear… (More)

Is this relevant?

Highly Cited

1973

Highly Cited

1973

- IEEE Transactions on Computers
- 1973

An mth-order recurrence problem is defined as the computation of the series x<inf>1</inf>, x<inf>2</inf>, ..., X<inf>N</inf… (More)

Is this relevant?