The decay constant of radioactive substance is 4.33 x 10^{-4} per year. Calculate its half life period.

Advertisement Remove all ads

#### Solution

Here, λ= 4.33 * 10^{−4} per year

t_{1/2 }= `0.6931/lambda`

∴ t_{1/2 =} `0.6931/lambda =0.6931/(4.33*10^-4)`

_{ }∴t_{1/2} = 1600.69 years or

t_{1/2} =0.16*10^{4}*365 days

∴t_{1/2} = 584000days

Concept: Law of Radioactive Decay

Is there an error in this question or solution?

#### APPEARS IN

Advertisement Remove all ads