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m=0 2, we have I.M.ff n (J)g 1 n=0 2. This implies lim n!1 jf n (J)j = 0. By inequality 6, we have lim k!1 jJ k j = 1. It contradicts that jJ k j jIj. 2 Now, we prove Theorem B. Assume that fp i g 1(More)
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