P. B. Sreeja

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The title compound, C14H12FN3O, adopts an E conformation with respect to the azomethine bond. The pyridyl and fluoro-benzene rings make dihedral angles of 38.58 (6) and 41.61 (5)° respectively with the central C(=O)N2CC unit, resulting in a non-planar mol-ecule. The inter-molecular inter-actions comprise two classical N-H⋯O and N-H⋯N hydrogen bonds and four(More)
The title molecule, C(13)H(13)N(3)O(3).H(2)O, is in the form of a monohydrated zwitterion. The tetrahydropyridinium ring adopts an envelope conformation and is nearly coplanar with the plane of the imidazoline ring. The water solvate molecule plays an important role as a bridge between zwitterions, forming molecular chains running along the c direction,(More)
The title compound, C14H12FN3O, adopts an E conformation with respect to the azomethine double bond whereas the N and methyl C atoms are in a Z conformation with respect to the same bond. The ketonic O and azomethine N atoms are cis to each other. The non-planar mol-ecule [the dihedral angle between the benzene rings is 7.44 (11)°] exists in an amido form(More)
The asymmetric unit of the title compound, C14H11FN2O, contains two independent mol-ecules, both of which adopt the E conformation with respect to the azomethine C=N bond. The mol-ecules are non-planar, with dihedral angles of 26.92 (12) and 11.36 (11)° between the benzene and phenyl rings. In the crystal, mol-ecules are linked through N-H⋯O=C and N-H⋯N(More)
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