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A manifold is a connected Hausdorff space in which every point has a neighborhood homeomorphic to Euclidean n-space (n is unique). A space is collec-tionwise Hausdorff (cwH) if every closed discrete subspace D can be expanded to a disjoint collection of open sets each of which meets D in one point. There are exactly two examples of 1-dimensional… (More)

- Ann Hibner Koblitz, Lenore Blum, +4 authors Mary Ellen Rudin
- 1998

Book Review ways in which the practices and ideology of this [math-ematical] community create an atmosphere that prevents women from being completely accepted as full-fledged mem-bers? " (p. xvii) Addressing this question meant that Henrion would have to identify the " ideology " of the mathematical community and investigate the impact of this ideology on… (More)

We prove that if µ + < λ = cf(λ) < µ ℵ 0 for some regular µ > 2 ℵ 0 , then there is no family of less than µ ℵ 0 c-algebras of size λ which are jointly universal for c-algebras of size λ. On the other hand, it is consistent to have a cardinal λ ≥ ℵ 1 as large as desired and satisfying λ <λ = λ and 2 λ + > λ ++ , while there are λ ++ c-algebras of size λ +… (More)

- JAN VAN MILL, A. V. ArhangeΓskiϊ, Mary Ellen Rudin
- 2004

We give an example of a first countable, hereditarily normal, homogeneous Eberlein compact space which is not metrizable. This answers a question of A. V. ArhangeΓskiϊ. 1* Introduction* A compact Hausdorff space is called Eberlein compact, if it is homeomorphic to a weakly compact subset of a Banach space. For information concerning Eberlein compact spaces,… (More)

- Mary Ellen Rudin
- 2001

- Grace Wahba, UGrad, Mary Ellen Rudin, Marigold Melli
- 2013

Links to these slides in my website

- Scott W. Williams, Haoxuan Zhou, Mary Ellen Rudin
- 2010

For a compact monotonically normal space X we prove: (1) X has a dense set of points with a well-ordered neighborhood base (and so X is co-absolute with a compact orderable space); (2) each point of X has a well-ordered neighborhood π-base (answering a question of Arhangel'skii); (3) X is hereditarily paracompact iff X has countable tightness. In the… (More)

- MARY ELLEN RUDIN
- 2010

In this paper we prove that the product of countably many scattered paracompact spaces is even ultraparacompact. Telgársky [1] has shown that scattered paracompact spaces are ultraparacompact. Verbally, H. Martin has asked if a product of countably many spaces with exactly one nonisolated point has to be paracompact. We prove Theorem. The product of… (More)

- M. E. Rudin
- 2007