Mark Babikov

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In this paper we show how to construct an isomorphism between an alternative algebra A over a field of characteristic 6= 3 and its isotope A(1+c), where c is an element of Zhevlakov’s radical of A. This leads to the equivalence of any polynomial identity f = 0 in alternative algebras and the isotope identity f(s) = 0. Given an invertible element s of an(More)
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