Eva Burrows

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T-2 toxin is a potent cytotoxic metabolite produced by the Fusarium species. The fate and distribution of 3H-labeled T-2 toxin were examined in male guinea pigs. Radioactivity was detected in all body tissues within 30 min after an im injection of an LD50 dose (1.04 mg/kg) of T-2 toxin. The plasma concentration of trichothecene molar equivalents versus time(More)
One of the major issues in parallelizing applications is to deal with the inherent dependency structure of the program. Dependence analysis provides execution-order constraints between program statements, and can establish legitimate ways to carry out program code transformations. The concept of data dependency constitutes one class of dependencies obtained(More)
Treatment of deoxynivalenol [3] in MeOH with hypochlorite bleach containing added NaOH gave rise to a single major product, the 9 alpha, 10 alpha, 12 beta, 13 beta-diepoxy-8,15-hemiketal 4. Thus, the reaction followed a very different course from that observed for verrucarol [2], where rearrangement involving opening of the starting 12,13-epoxide and a(More)
With the appearance of low-cost, highly parallel hardware architectures, software portability between such architectures is in great demand. Software design lacks programming models to keep up with the continually increasing parallelism of today’s hardware. This setting calls for alternative thinking in programming. When a computation has a static(More)
The CUDA execution model of Nvidia’s GPUs is based on the asynchronous execution of thread blocks, where each thread executes the same kernel in a data-parallel fashion. When threads in di↵erent thread blocks need to synchronise and communicate, the whole computation launched onto the GPU needs to be stopped and re-invoked in order to facilitate interblock(More)
rg(p, b) = ! ( row(p) =1 && sbf(p) =0) rp(p, b) = if ( ( ( sbf(p) >1) and (0<=row(p) <=sbf(p) -2) ) or ( ( sbf(p) =1) and (row(p) =0) ) ) then if (b=0) then BSh( sbf(p) , row(p) +1, col(p) ) else BSh( sbf(p) , row(p) +1, flip(row(p) , col(p) ) ) else if ( ( sbf(p) >1) and (row(p) =sbf(p) -1) ) then if (b=0) then BSh( sbf(p) -1, 0, col(p) ) else BSh( sbf(p)(More)
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