David S. Flamm

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An uncorrected version of HQR3 will yield a division by zero in line HQR 1060 of [2] as a result of the test in (1). In checking for a zero subdiagonal element, the criterion is the sum of the magnitudes of the two diagonals. As the example shows, when both diagonals are zero, the .LT. test fails for an exactly zero subdiagonal element. Without correction(More)
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